3y^2+40y+13=

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Solution for 3y^2+40y+13= equation:


Simplifying
3y2 + 40y + 13 = 0

Reorder the terms:
13 + 40y + 3y2 = 0

Solving
13 + 40y + 3y2 = 0

Solving for variable 'y'.

Factor a trinomial.
(13 + y)(1 + 3y) = 0

Subproblem 1

Set the factor '(13 + y)' equal to zero and attempt to solve: Simplifying 13 + y = 0 Solving 13 + y = 0 Move all terms containing y to the left, all other terms to the right. Add '-13' to each side of the equation. 13 + -13 + y = 0 + -13 Combine like terms: 13 + -13 = 0 0 + y = 0 + -13 y = 0 + -13 Combine like terms: 0 + -13 = -13 y = -13 Simplifying y = -13

Subproblem 2

Set the factor '(1 + 3y)' equal to zero and attempt to solve: Simplifying 1 + 3y = 0 Solving 1 + 3y = 0 Move all terms containing y to the left, all other terms to the right. Add '-1' to each side of the equation. 1 + -1 + 3y = 0 + -1 Combine like terms: 1 + -1 = 0 0 + 3y = 0 + -1 3y = 0 + -1 Combine like terms: 0 + -1 = -1 3y = -1 Divide each side by '3'. y = -0.3333333333 Simplifying y = -0.3333333333

Solution

y = {-13, -0.3333333333}

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